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-.003x^2+0.14+8=0
We add all the numbers together, and all the variables
-0.003x^2+8.14=0
a = -0.003; b = 0; c = +8.14;
Δ = b2-4ac
Δ = 02-4·(-0.003)·8.14
Δ = 0.09768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.09768}}{2*-0.003}=\frac{0-\sqrt{0.09768}}{-0.006} =-\frac{\sqrt{}}{-0.006} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.09768}}{2*-0.003}=\frac{0+\sqrt{0.09768}}{-0.006} =\frac{\sqrt{}}{-0.006} $
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